開方(x-2)^2大過等於2x+5
搵個possible values of x
點計呀??
A-maths問題!!!
2006-12-15 5:42 am
回答 (5)
2006-12-15 1:42 pm
✔ 最佳答案
開方(x-2)^2大過等於2x+5(x-2)=2x+5 x can be negative or positive therefore square both side
x^2-4x+4>=4x^2+20x+25
3x^2+24x+21<=0
(3x+21)(x+1)<=0
3x=-21 x=-1
x=-7
-1>=x>=-7
2006-12-15 6:03 am
So Easy:
x-2>=2x+5
-x>=7
x<=-7
x-2>=2x+5
-x>=7
x<=-7
2006-12-15 6:02 am
ecasy (x-2)=4 2x+5=12
all +together 160
all +together 160
2006-12-15 5:50 am
開方(x-2)^2大過等於2x+5
x-2>=2x+5
-x>=7
x<=-7
^^"
x-2>=2x+5
-x>=7
x<=-7
^^"
參考: 自己都學緊=]
2006-12-15 5:45 am
開方再2 次咁咪冇左lo,,
then,,
(x-2)>=2x+5
-x>=7
x=<-7
then,,
(x-2)>=2x+5
-x>=7
x=<-7
收錄日期: 2021-04-12 23:14:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061214000051KK04264