1.∫2X^2+8X-3/(X+2)^2 dx
答案:2x+11/x+2 +C
2.∫cos6Xcos2X dx
答案:1/8 sin4x+1/16 sin8+C
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am不定積分問題x2
2006-12-14 2:43 am
回答 (1)
2006-12-14 2:54 am
✔ 最佳答案
1.∫(2X^2+8X-3)/(X+2)^2 dx
=∫[2(x+2)^2-11]/(X+2)^2 dx
=∫2-11/(X+2)^2 dx
=2x+11/(x+2) +C
2
cos(A+B)+cos(A-B)=2cosAcosB
∫cos6Xcos2X dx
=1/2∫(cos6X+2x)+cos(6x-2X) dx
=1/2∫(cos8x)+cos(4x) dx
=1/8 sin4x+1/16 sin8+C
收錄日期: 2021-04-25 16:49:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061213000051KK03194