[幾何]MATHS~easy呀 20分!! 2日!!急!!

2006-12-12 8:01 am
http://i86.photobucket.com/albums/k113/chy684959/DSCN2533.jpg

噤呢個網入去睇果兩條數...(7,8) 好少咋!!
識幾多題就做幾多題la...thx....有20分架!!
要步驟...唔該...^^

回答 (2)

2006-12-12 8:13 am
✔ 最佳答案
7)

angleQPD = 100
angle ACB = 25 ( alt. angles, AD//BC )

y = angleQPD + angleACB (ext. angle of triangle)
= 25 + 100


angleBDC = 100 - 25 = 75
angleCPD = 80 ( angles on st line )

BDC + CPD + X = 180 ( angle sum of triangle)
X = 25


8)
angle PRQ = 45 ( property of square)
angle ABR = 60
angle SAQ = ABR + PRQ ( ext. angle of triangle)

明唔明啊> < ??

2006-12-12 00:16:06 補充:
啊...第七題第二part錯左 = =應該系angleBDC = 90 - 25 = 65angleCPD = 80 ( angles on st line )BDC CPD X = 180 ( angle sum of triangle)X = 35

2006-12-12 00:16:20 補充:
啊...第七題第二part錯左 = =應該系angleBDC = 90 - 25 = 65angleCPD = 80 ( angles on st line )BDC CPD X = 180 ( angle sum of triangle)X = 35

2006-12-12 00:16:31 補充:
啊...第七題第二part錯左 = =應該系angleBDC = 90 - 25 = 65angleCPD = 80 ( angles on st line )BDC CPD X = 180 ( angle sum of triangle)X = 35
參考: 我自己
2006-12-12 8:10 am
Q7

x + 90度 = 100度 + 25度 (ext. angle of triangle)
x = 35度

y = 90度 + x度 (ext. angle of triangle)
y = 90度 + 35度
y = 125度


Q8.

角ABR = 60度 (vert. opp angles)
角BRA = 45度
角SAQ = 60度 + 45度
角SAQ = 105度

2006-12-12 00:11:18 補充:
Q8.角ABR = 60度 (vert. opp angles)角BRA = 45度角SAQ = 60度 45度 (ext. angle of triangle)角SAQ = 105度


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