✔ 最佳答案
7)
angleQPD = 100
angle ACB = 25 ( alt. angles, AD//BC )
y = angleQPD + angleACB (ext. angle of triangle)
= 25 + 100
angleBDC = 100 - 25 = 75
angleCPD = 80 ( angles on st line )
BDC + CPD + X = 180 ( angle sum of triangle)
X = 25
8)
angle PRQ = 45 ( property of square)
angle ABR = 60
angle SAQ = ABR + PRQ ( ext. angle of triangle)
明唔明啊> < ??
2006-12-12 00:16:06 補充:
啊...第七題第二part錯左 = =應該系angleBDC = 90 - 25 = 65angleCPD = 80 ( angles on st line )BDC CPD X = 180 ( angle sum of triangle)X = 35
2006-12-12 00:16:20 補充:
啊...第七題第二part錯左 = =應該系angleBDC = 90 - 25 = 65angleCPD = 80 ( angles on st line )BDC CPD X = 180 ( angle sum of triangle)X = 35
2006-12-12 00:16:31 補充:
啊...第七題第二part錯左 = =應該系angleBDC = 90 - 25 = 65angleCPD = 80 ( angles on st line )BDC CPD X = 180 ( angle sum of triangle)X = 35