我數學有唔識 6(x-y)^2-z(y-x)+5x-5y
2(5x-3)^2-9(5x-3)+10
十萬火急..請連同計算步驟一同列出
數學一問........................................
2006-12-12 4:18 am
回答 (2)
2006-12-12 4:34 am
✔ 最佳答案
6(x-y)^2-z(y-x)+5x-5y=6(x-y)^2-z(y-x)+5(x-y)
=6(x-y)^2-zy+zx+5(x-y)
=6(x-y)^2+z(x-y)+5(x-y)
=(x-y)(6(x-y)+z+5)
=(x-y)(6x-6y+z+5)
2(5x-3)^2-9(5x-3)+10
=(5x-3)(2(5x-3)-9)+10
=(5x-3)(10x-15)+10
=50x^2-105x+55
=(50x+55)(-x-1)
2006-12-22 4:03 am
6(x-y)^2-z(y-x)+5x-5y
=6(x-y)^2-z(y-x)+5(x-y)
=6(x-y)^2-zy+zx+5(x-y)
=6(x-y)^2+z(x-y)+5(x-y)
=(x-y)(6(x-y)+z+5)
=(x-y)(6x-6y+z+5)
2(5x-3)^2-9(5x-3)+10
=(5x-3)(2(5x-3)-9)+10
=(5x-3)(10x-15)+10
=50x^2-105x+55
=(50x+55)(-x-1)
=6(x-y)^2-z(y-x)+5(x-y)
=6(x-y)^2-zy+zx+5(x-y)
=6(x-y)^2+z(x-y)+5(x-y)
=(x-y)(6(x-y)+z+5)
=(x-y)(6x-6y+z+5)
2(5x-3)^2-9(5x-3)+10
=(5x-3)(2(5x-3)-9)+10
=(5x-3)(10x-15)+10
=50x^2-105x+55
=(50x+55)(-x-1)
收錄日期: 2021-04-13 19:03:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061211000051KK03753