中一maths

Let $ x be 一套便服的價錢
西裝的價錢 = $6x

6x +x =1540
x=220

一套西裝的價錢一套便服的價錢 = 6x -x =5x = 1100


Let $ x 光英得
Then 惠英所得 = 3/2 x +100

3/2 x + 100 +x = 2500
x=960

惠英分得3/2 x +100=1540

1.西裝的價錢是:1540/7*6
=$1320
一套便服的價錢是:1540/7
=$220
一套西裝的價錢一套便服的價錢相差:1320-220=$1100

2.惠英得$X,光英得$Y
2500=X+Y
X=Y*3/2+100
2500=Y*3/2+100+y
2500-100=y*5/2
2400*2/5=Y
Y=960
X=2500-960
X=1540
惠英得$1540

1. Let 一套西裝 be x,
x+x/6=1540
6(x+x/6)=1540*6
6x+x =9240
7x=9240
x=1320
1320-(1320/6)
=1320-220
=1100

2.Let 光英分得 $x
x+(3/2x+100)=2500
2x+3x+200=5000
5x =4800
x=$960
2500-960=$1540(惠英)

(1)
設便服的價錢是$y,則西裝的價錢是$6y
y+6y=1540
7y=1540
y=220
所以便服的價錢是$220,西裝的價錢是$220x6=$1320
它們價錢相差:$1320-$220=$1100

(2)
設光英得$y,則惠英得$(3y/2 +100)
y+(3y/2+100)=2500
5y/2 +100=2500
5y+200=5000
5y=4800
y=960
所以光英得$960,則惠英得$2500-$960=$1540

1.y+6y=1540

7y=1540

y=220

y+2y/3 =2500

5y/3=2400

y1450

1. 便服的價錢 = x, 西裝的價錢= 6x
x + 6x = 1540
7x = 1540
x = 220

6x - x = 5x = 1100
西裝便服的價錢相差 $1100

2. 光英分得 = y , 惠英分得 = 2y/3 +100
y + 2y/3 +100 = 2500
5y/3=2400
y = 1440

2y/3 +100 = 1060
惠英分得 $1060