I really need help with this problem... math geniuses needed?
2006-12-07 3:40 pm
If a virus spreads from 100 computers to 1,000,000 in 120 minutes and the equation is A(base of t)=A(base 0)e^kt , an original virus in 500 computers in 360 minutes?
回答 (5)
2006-12-07 3:45 pm
✔ 最佳答案
1000000=100e^120ke^120k=10000
120k ln e=ln10000
120k=ln 10000
k=ln10000/120
now once k is known the equation is known
plug and chug
2006-12-08 12:27 am
If a virus spreads from 100 computers to 1,000,000 in 120 minutes then a virus spreads from 1 computer to10,000 computers in 120 minutes.
At = Aoe^kt
10^4 = e^120k
log 10^4 = log e^120k
4= 120k log e
k = 4/(120log e) = 4/(120 * .43429) = .077
At = e^.077*360 =e^27.72
So 500 computers will spread 500e^27.72 viruses in 320 minutes. This is approximately 5.465*10^14 viruses.
At = Aoe^kt
10^4 = e^120k
log 10^4 = log e^120k
4= 120k log e
k = 4/(120log e) = 4/(120 * .43429) = .077
At = e^.077*360 =e^27.72
So 500 computers will spread 500e^27.72 viruses in 320 minutes. This is approximately 5.465*10^14 viruses.
2006-12-07 11:49 pm
You can do the calculation but I will give you a hint.
At time zero, A(t) = 100 = Ao
At time = 120 minute, A(t) = 1000000.
So A(t) = 100*e^k(120) = 1000000.
From this equation, calculate k.
Then in the second case, Ao = 500, t = 360. Use the k you obtain above to calculate A(t).
At time zero, A(t) = 100 = Ao
At time = 120 minute, A(t) = 1000000.
So A(t) = 100*e^k(120) = 1000000.
From this equation, calculate k.
Then in the second case, Ao = 500, t = 360. Use the k you obtain above to calculate A(t).
2006-12-07 11:48 pm
I'm guessing you mean 'A sub 0' and 'A sub t' but the rest of the question is lost on me. What are A sub t and A sub 0? Are you looking for the k-value, or what? And what does the last part mean?
Doug
Doug
2006-12-07 11:48 pm
the answer is 2.5657676
i am a teacher
i am a teacher
收錄日期: 2021-05-03 14:21:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061207074029AAE4lez