In a bookshop,the profit made by selling a calendar is $18.After 2/5 of the calendars are sold,the bookseller reduces the price of each calendar by$10.When all the calendars are sold,the bookseller makes an overall profit of$3000.
(a.)Find the total number of calendars he has originally.
(b.)Suppose the bookseller can only sell a further 100 calendars after the price reduction.and the discard all the remaining calendars.Find the total cost of the calendars if the overall profit per cent is 20%
Maths questions???(5)
2006-12-08 4:09 am
回答 (2)
2006-12-08 4:23 am
✔ 最佳答案
(a) Let x be the total number of calendars he has originally.18 (2x / 5) + (18 - 10) (3x / 5) = 3000
36x / 5 + 24x / 5 = 3000
60x = 15000
x = 250
Therefore, he has 250 calendars originally.
(b) The number of calendars he has sold in the original price
= 250 (2 / 5)
= 100
The total cost of the calendars
= [18 (100) + (18 - 10) (100)] / 20%
= [1800 + 800] (5)
= 2600 (5)
= $13000
參考: 自己
2006-12-08 4:17 am
(a)
Assume the total number of calendars he has originally is x
then
2/5*x*18+3/5*x*8=3000 (since less $10 means profit becomes $8)
7.2x+4.8x=3000
x=250
the total number of calendars he has originally is 250
(b)
The total profit
=2/5*250*18+100*8
=2600
let the cost is C
then
2600/C=20%
2600=0.2C
2600=0.2C
C=13000
the cost is 13000
Assume the total number of calendars he has originally is x
then
2/5*x*18+3/5*x*8=3000 (since less $10 means profit becomes $8)
7.2x+4.8x=3000
x=250
the total number of calendars he has originally is 250
(b)
The total profit
=2/5*250*18+100*8
=2600
let the cost is C
then
2600/C=20%
2600=0.2C
2600=0.2C
C=13000
the cost is 13000
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