數學(maths)

2006-12-08 12:48 am
2(3y-7)-5(y-2)=6(y-4)

要式唔該

回答 (7)

2006-12-08 12:52 am
✔ 最佳答案
(6y - 14) - (5y - 10) = 6y-24
6y - 14 - 5y + 10 = 6y - 24
y - 4 = 6y - 24
-4 + 24 = 6y - y
20 = 5y
y = 4
2006-12-08 1:03 am
2(3y-7)-5(y-2)=6(y-4)
6y-14-5y+10=6y-24
5y=20
y=4
2006-12-08 12:55 am
6y-14-5y+10=6y-24
6y-5y-14+10=6y-24
y-4=6y-24
5y=20
y=4
2006-12-08 12:53 am
2(3y-7)-5(y-2)=6(y-4)
6y-42-5y-10=6y-24
6y-5y-6y=-24+42+10
-5y=76
y=15.2

2006-12-07 16:54:33 補充:
sorry2(3y-7)-5(y-2)=6(y-4)6Y-14-5Y 10=6Y-24-5Y=-20Y=4
2006-12-08 12:53 am
6y-14-5y+10=6y-24
y-4 =6y-24
-5y= -20
y=4
2006-12-08 12:53 am
2(3y-7)-5(y-2)=6(y-4)
6y-14-5y+10=6y-24
-14+10+24=6y-6y+5y
20=5y
y=20/5
y=4
2006-12-08 12:52 am
2(3y-7)-5(y-2)=6(y-4)
6Y-14-5Y+10=6Y-24
-5Y=-20
Y=4


收錄日期: 2021-04-13 14:13:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061207000051KK02284

檢視 Wayback Machine 備份