已知函數ｙ＝３ｘ＾２＋９ｘ－６．當ｘ是下列的值時，求ｙ．．．唔該比條橫式我

ｙ＝３ｘ^２＋９ｘ－６
a) y=3(1)^2+９(1)－６
=3+9-6
=6
b) Y=３(0)^２＋９(0)－６
= -6
c) Y=３(b)^２＋９(b)－６
=3b^2+9b-6
d) y=３(c/3)^２＋９(c/3)－６
=(c^2)/3+3c-6

３(１)^2+9(1)-6
=3+3
=6

３(０)^2+9(0)-6
=-6

３ｂ＾２＋９b－６

３(３分ｃ)＾２＋９(３分ｃ)－６

a) y=3x^2+9x-6
y=3(1)^2+9(1)-6
y=9+9-6
y=12


b) y=3x^2+9x-6
y=3(0)^2+9(0)-6
y=-6


c) y=3x^2+9x-6
y=3(b)^2+9(b)-6
y=3b^2+9b-6


d) y=3x^2+9x-6
y=3分2c+3c-6


應該差不多la
hope can help you