✔ 最佳答案
a.
當x = 1時,把x = 1代入函數y = 3x² + 9x - 6,得出:
y = 3(1)² + 9(1) - 6 = 3 + 9 - 6 = 6
b.
當x = 0時,把x = 0代入函數y = 3x² + 9x - 6,得出:
y = 3(0)² + 9(0) - 6 = 0 + 0 - 6 = -6
c.
當x = b時,把x = b代入函數y = 3x² + 9x - 6,得出:
y = 3(b)² + 9(b) - 6 = 3b² + 9b - 6【或 3(b² + 3b - 2)】
d.
c.
當x = c/3時,把x = c/3代入函數y = 3x² + 9x - 6,得出:
y = 3(c/3)² + 9(c/3) - 6
= 3(c²/9) + 3c - 6
= c²/3 + 3c - 6【或 1/3 * (c² + 9b - 18)】
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