Physics 電路問題

It Is true For Resistance and Inductance only

When 2 Resistor are Connected in Series, Total Resistance = R1 + R2
For a 100m cable, it's Resistance is a, so that the Resistance of a 50m Cable = a/2 so that 2 serial 50m cable(1 100m cable)

Similarly, the inductors in series have the floowing Property: Total Inductance = L1 + L2

But for the Capacitance in Series,
1/Ct = (1/C1) + (1/C2)
Just like the resistor in Paralle
In this case, C1 = C2 as they are cable with same length and width
1/c = 2/C1
c = (C1) /2
C1= 2c
Oh man, Got a Double...
So in the case of Capacitance, it isnt just divide it by 2

All calculation is assumed that the R,C,I are depended on the witdh and the length of the cable only

虧佬四's answer for resistance and inductance is true, but I don't agree with the answer for capacitance, since the capacitance of a capacitor is proportional to the area of the electro plates, therefore if the width remains the same and length is half, the area becomes half, and thus the capacitance reduces to half, therefore the shorter the cable, the less is the capacitance.