因式分解問題:(中學)
回答 (6)
2006-12-06 7:50 am
✔ 最佳答案
"應該"係:(2x-3)^2+10x-15
=4x^2-12x+9+10x-15
=4x^2-12x+10x-15+9
=4x^2-2x-6
=(2x-3)(2x+2)
2006-12-08 8:39 pm
(2x-3)(2x-3+5)
(2x-3)(2x+2)
2(2x-3)(x+1)
(2x-3)(2x+2)
2(2x-3)(x+1)
2006-12-07 3:11 am
(2x-3)^2+10x-15
=(2x-3)(2x-3)+5(2x-3)
=(2x+2)(2x-3)
=2(x+1)(2x-3)
=(2x-3)(2x-3)+5(2x-3)
=(2x+2)(2x-3)
=2(x+1)(2x-3)
2006-12-06 7:44 am
(2x-3)^2+10x-15
= (2x-3)^2+5 (2x-3)
= (2x-3) [ (2x-3) + 5]
= (2x-3) (2x - 3 + 5)
= (2x-3) (2x+2)
= 2(2x-3) (x+1)
= (2x-3)^2+5 (2x-3)
= (2x-3) [ (2x-3) + 5]
= (2x-3) (2x - 3 + 5)
= (2x-3) (2x+2)
= 2(2x-3) (x+1)
參考: me
2006-12-06 7:44 am
(2x-3)^2 + 10x - 15
=4x^2 - 12x + 9 + 10x - 15
=4x^2 - 2x - 6
=(x+1)(2x-3)
=4x^2 - 12x + 9 + 10x - 15
=4x^2 - 2x - 6
=(x+1)(2x-3)
參考: me
2006-12-06 7:44 am
(2x-3)² + 10x - 15
= (2x-3)(2x-3) + 5(2x-3)
= (2x-3)[(2x-3) + 5]
= (2x-3)(2x-3+5)
= (2x-3)(2x+2)
= 2(2x-3)(x+1)
= (2x-3)(2x-3) + 5(2x-3)
= (2x-3)[(2x-3) + 5]
= (2x-3)(2x-3+5)
= (2x-3)(2x+2)
= 2(2x-3)(x+1)
收錄日期: 2021-04-12 22:06:53
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