y=2x/5x+1 (x属於R,且Ｘ不等於－０．２）
解：Y(5X+1)=2X
5YX+Y=2X
做到這裡就不會,請各位指教一下,謝謝!
一個反函數的問題
2006-12-06 7:30 am
回答 (2)
2006-12-06 7:37 am
✔ 最佳答案
y=2x/(5x+1)y(5x+1)=2x
5xy+y=2x
5xy-2x=-y
x(5y-2)=-y
x=y/(2-5y)
2006-12-05 23:57:04 補充：
y=(x-1)/(x+1)y(x+1)=x-1xy+y=x-1xy-x=-(1+y)x(y-1)=-(1+y)x=(1+y)/(1-y)
2006-12-06 7:47 am
這也是主項轉移的問題
y = (2x) / (5x + 1)
y (5x + 1) = 2x
5xy + y = 2x
y = 2x - 5xy
y = x (2 - 5y)
y / (2 - 5y) = x
x = y / (2 - 5y)
y = (2x) / (5x + 1)
y (5x + 1) = 2x
5xy + y = 2x
y = 2x - 5xy
y = x (2 - 5y)
y / (2 - 5y) = x
x = y / (2 - 5y)
參考: me
收錄日期: 2021-04-12 22:50:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061205000051KK05310