4a+5b-2a+b=(4a-2a)+(5b+b)

2006-12-06 3:52 am
係計代數式

回答 (7)

2006-12-06 4:00 am
✔ 最佳答案
4a+5b-2a+b=(4a-2a)+(5b+b)
2a+6b=2a+6b
2a-2a=+6b-6b
0=0
a=0 b=0
參考: me
2006-12-07 3:26 am
4a+5b-2a+b
=4a-2a+5b+b
=(4a-2a)+(5b+b)
=2a+6b
=2(a+3b)
2006-12-06 4:30 am
R.H.S=4a+5b-2a+b=2a+6b
L.H.S=4a-2a+5b+b=2a+6b
so it's an identity.
2006-12-06 4:05 am
4a+5b-2a+b=(4a-2a)+(5b+b)
4a+5b-2a+b=4a-2a+5b+b
2a+6b=2a+6b
2a-2a=6b-6b
0=0

2006-12-05 20:07:21 補充:
i.e. 2a+6b
2006-12-06 4:04 am
4a+5b-2a+b
= 2a + 6b
2006-12-06 3:58 am
4a+5b-2a+b
=4a-2a+5b+b
=2a+6b
2006-12-06 3:56 am
4a+5b-2a+b
=4a-2a+5b+b
=(4a-2a)+(5b+b)


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