請幫幫我解答以下問題，thx a lot....
1. Make r as the subject of the formula.
A = P( 1 + rt / 100)
2. Factorize - (1 - x) - (x - 1)²
中二的一些數學難題 (15 點)
2006-12-06 12:46 am
回答 (5)
2006-12-06 1:10 am
✔ 最佳答案
For Q2-(1-x) - (x-1)^2
= -1+x - (x^2 - 2x +1)
= -1+x -x^2 +2x -1
= -x^2 + 3x - 2
= - (x^2 - 3x + 2)
= - (x - 2)(x - 1)
2006-12-06 2:31 am
A = P( 1 + rt / 100) [r]
A/P=1 + rt / 100
A/P-1= rt / 100
100(A/P-1)=rt
[100(A/P-1)]/t=r
r=[100(A/P-1)]/t
2.- (1 - x) - (x - 1)²
= - (1 - x) + (1 - x)(1 - x)
= - (1 - x) x [(1 - x)+1]
= - (1 - x)(2 - x)
A/P=1 + rt / 100
A/P-1= rt / 100
100(A/P-1)=rt
[100(A/P-1)]/t=r
r=[100(A/P-1)]/t
2.- (1 - x) - (x - 1)²
= - (1 - x) + (1 - x)(1 - x)
= - (1 - x) x [(1 - x)+1]
= - (1 - x)(2 - x)
參考: 數學能手Me
2006-12-06 1:05 am
1. A/P=1+rt/100
(A/P)-1=rt/100
{[(A/P)-1]*100}/t=r
r={[(A/P)-1]*100}/t
2 =-X^2+2X-1+1-X
=-X^2+X
(A/P)-1=rt/100
{[(A/P)-1]*100}/t=r
r={[(A/P)-1]*100}/t
2 =-X^2+2X-1+1-X
=-X^2+X
參考: 梁宇軒
2006-12-06 1:00 am
1. A=P(1+rt/100)
A/P=1+rt/100
A/P-1=RT/100
[100(A/P-1)]/T =R
2. -(1-X)-(x-1)^2
=-1+x-(x^2 -2x+1)
=-1+x-x^2 +2x-1
=x^2-3X+2
=(x-1)(x-2)
A/P=1+rt/100
A/P-1=RT/100
[100(A/P-1)]/T =R
2. -(1-X)-(x-1)^2
=-1+x-(x^2 -2x+1)
=-1+x-x^2 +2x-1
=x^2-3X+2
=(x-1)(x-2)
2006-12-06 12:58 am
1. A/P=1+rt/100
(A/P)-1=rt/100
{[(A/P)-1]*100}/t=r
r={[(A/P)-1]*100}/t
2 =-X^2+2X-1+1-X
=-X^2+X
(A/P)-1=rt/100
{[(A/P)-1]*100}/t=r
r={[(A/P)-1]*100}/t
2 =-X^2+2X-1+1-X
=-X^2+X
參考: myself
收錄日期: 2021-04-12 19:08:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061205000051KK02038