What is the answer of this fomula?

(a-x)*(b-x)*(c-x)...*(z-x)=1 !!
Because one of the terms will be ( x-x ) , and this equals 0 . As we know that , a^o is always 1! ( a is for all values , except 0 )

a*0 = 0 (a multiplied by 0 is 0),
a^0 = 1 (a to the power of 0 is 1),
thus a*0 is not a^0 by all means.

A wrong answer is chosen instead of the other correct one.
It's a pity!

u r wrong the answer should be 0
while * is for times and ^ is for index...
(...)*(x-x) = (...)*0 = 0

I think the below mean that the answer is 0

because (x-x)=0, so the entire product is zero.