一條方程式,求x
以下為一條方程式,求x。
2(3x+9)+9(5x+20) = 606
x=?
回答 (18)
✔ 最佳答案
2(3x+9)+9(5x+20) = 606
6x+18+45x+180=606
51x+198=606
51x=408
x=8
參考: myself
2(3x+9)+9(5x+20) = 606
6x+18+45x+180 = 606
51x + 198 = 606
51x = 408
x = 8
2(3x+9)+9(5x+20) = 606
6x+18+45x+180 = 606
51x+198=606
51x=606-198
51x=408
x=8
參考: me
2(3x+9)+9(5x+20) = 606
2x3x+2x9+9x5x+9x20=606
6x+18+45x+180=606
51x+198=606
51x=606-198
51x=408
x=8
參考: me
2(3X +9) + 9(5X +20) = 606
6X + 18 + 45X+180 = 606
51X = 606 - 18 - 180
X= 8
參考: ME
6x+18+45x+180=606
51x+198=606
51x=408
x=8
2(3x+9)+9(5x+20)=606
6x+18+45x+180=606
51x=408
x=8
2(3x+9)+9(5x+20)=606
6x+18+45x+180=606
51x+198=606
51x=408
x=8
參考: me
6x + 18 + 45x + 180 = 606
51x = 408
x = 8
2(3x+9)+9(5x+20) = 606
6x + 18 + 45x + 180 = 606
51x = 408
x = 8
收錄日期: 2021-04-12 22:04:41
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