急問數學題~

2006-12-05 1:51 am
Factorize the following expressions

1.36x² -49y² ----------------------ans:(6x-7y)(6x+7y)

2. a² +20a+100----------------------ans:(a+10)²

3.a² +4ab+4b² ----------------------ans:(a+2b)²

4.36x² +12xy+y² ----------------------ans:(6x+y)²

5.x² -12x+36 ----------------------ans:(x-6)²

6. 16x² -8x+1 ----------------------ans:(4x-1)²

回答 (2)

2006-12-05 2:00 am
✔ 最佳答案
1.36x² - 49y²
= (6x)² - (7y)²
= (6x-7y)(6x+7y)

2. a² + 20a + 100
= a² + 2(10)a + (10)²
= (a+10)²

3.a² + 4ab + 4b²
= a² + 2a(2b) + (2b)²
= (a+2b)²

4.36x² + 12xy + y²
= (6x)² + 2(6x)y + y²
= (6x+y)²

5.x² -12x+36
= x² -2(6)x+(6)²
= (x-6)²

6. 16x² -8x+1
= (4x)² -2(4x)+1
=(4x-1)²
2006-12-05 1:56 am
你可以記住一些公式 : 

a ^ 2 - b ^ 2 = (a + b ) (a-b)
(a+b) ^2 = a ^2 + 2ab + b ^2

已可以全部解決你的問題。


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