Challenge!

2006-12-04 9:16 am
Using the sine law,
sinA/a=sinB/b=sinC/c

In triangle DEF, where angle E = 144, e = 10.5m, f = 12.5m, determine the no. of possible triangles that could be drawn. Then, find the measures of other angles in each possible triangle.

Thanks!
更新1:

Is there a situation that the angle E is an exterior angle?

回答 (1)

2006-12-04 3:59 pm
✔ 最佳答案
By sine law,

sinE/e = sinF/f

sin144°/10.5m = sinF/12.5m

sinF = (12.5/10.5)sin144°

sinF = (25/21)sin144°

sinF = 0.6997

F = 44.4065° or 135.5935°

For E = 144°, F = 44.4065°,

D = 180° - 144° - 44.4065°
D = -8.4064° (rejected as < 0)

For E = 144°, F = 44.4065°,

D = 180° - 144° - 135.5935°
D = -99.5935° (rejected as < 0)

So it's impossible for such situation and so no solution.

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Actually, for an angle more than 90°, it should have the longest length in the respective side. (e.g. angle E and side e). If the respective side of the angle more than 90° is not the longest, it's of no solution.

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By the way, the sine law is not applicable to an exterior angle.

For all the angles in the sine law,

sinA/a=sinB/b=sinC/c

0° < A < 180°, 0° < B < 180°, 0° < C < 180°



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