續多項式的問題II
回答 (2)
2006-12-03 12:25 am
✔ 最佳答案
樓上朋友的答案不對!(x²-x+2)(x²+x-2) - (x-2)²
= [(x²)-(x-2)][(x²+(x-2)] - (x-2)²
= [(x²)² - (x-2)²] - (x-2)²
= x^4 - 2 (x-2)²
= x^4 - 2x² + 8x - 8
2006-12-02 11:26 pm
=(X^2+X+2)(X^2+X-2)-(X-2)(X-2)
=(X^4)+(X^3)-(2X^2)+(X^3)+(X^2)-(2X)+(2X^2)+(2X)-4
=X^4+2X^3+X^2-4
=(X^4)+(X^3)-(2X^2)+(X^3)+(X^2)-(2X)+(2X^2)+(2X)-4
=X^4+2X^3+X^2-4
參考: 自己
收錄日期: 2021-04-18 20:22:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061202000051KK02466