differentiation problem(10 points)

F'(x) = x/5000 - 2000/x^2 - 1/20.

Differentiate a constant (20 in this case) = 0.

In general, d/dx (ax^n) = nax^(n-1), where a and n are constants.

So for 2000/x:
2000/x^2 = 2000x^(-1)
Differentiate wrt x gives -2000x^(-2) = -2000/x^2