How do you solve x^2-2x+2=0?
Split it up into y=x^2-6, and something else.
Please.
Here is an example of how you do it:
x^2-x-12=0
x^2-x-6-6=0
x^2-6=x+6
here it is.
equations!!
2006-12-01 4:42 pm
回答 (3)
2006-12-01 4:56 pm
✔ 最佳答案
X^2-2X+2=0X^2-2X-6+8=0
X^2-6=2X-8
2006-12-01 11:22 pm
x^2-2x+2=0
x^2-2x-6+8=0
y-2x+8=0
y=2x-8
If we have to solve x^2-2x+2=0
x^2-2x+2=0
x=(4士(4-8)sqrt.)/2
=2士i
x^2-2x-6+8=0
y-2x+8=0
y=2x-8
If we have to solve x^2-2x+2=0
x^2-2x+2=0
x=(4士(4-8)sqrt.)/2
=2士i
2006-12-01 5:12 pm
x^2-2x+2=0
x^2 - 6 - 2x + 8 = 0
Put y = x^2 - 6
y = 2x - 8
x^2 - 6 - 2x + 8 = 0
Put y = x^2 - 6
y = 2x - 8
收錄日期: 2021-04-23 00:09:31
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