FA數學題..(有10分""趕急)

2006-12-01 5:21 am
If (17/19)^5x-3=1, find the value of x.
更新1:

係 (17/19)^(5x-3)=1 點解無啦啦5x-3會=0??

回答 (2)

2006-12-01 5:33 am
✔ 最佳答案
題目5清楚...係{(17/19)^5x}-3=1----(1)定(17/19)^(5x-3)=1 -----(2)

CASE1:{(17/19)^5x}-3=1
(17/19)^5x=4
5x(log17-log19)=log4
x=log4/5(log17-log19)

case2: (17/19)^(5x-3)=1
5x-3=0
x=3/5
參考: BY EASON-MENSA
2006-12-01 6:53 am
(17/19)^(5x-3)=1
(5x-3)ln(17/19)=0
5x-3=0
x=3/5


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