中一題目 請解答

1) 6-(2-4t)/7=4
6-4=(2-4t)/7
2=(2-4t)/7
14=2-4t
-4t=12
t=-3


2) 4-(8-k)/5=(2k/5)
20-(8-k)=2k
20-8+k=2k
k=12

呢題-0- 括號唔齊 唔明 試下
3) (9/2)+8+k/6=(10+3k)/5
45/2+40+5k/6=10+3k
135+240+5k=60+18k
13k=315
k=315/13

2006-11-29 22:14:08 補充：
我明喇=0="3)((9/2) 8 k)/6=(10 3k)/5 係唔係咁呢 5*((9/2) 8 k)=6*(10 3k) 45/2 40 5k=60 18k 45 80 10k=120 36k 5=26kk=5/26

2006-11-30 18:39:10 補充：
3) (9/2) (8 k/6)=(10 3k/5) 第三題 (9/2)*30 (8 k/6)*30=(10 3k/5)*30 (*30係因為佢係2,6,5既L.C.M.) 135 240 5k=300 18k 75=13k k=75/13 k=5又 10/13

6 - (2-4t/7) = 4
6 = 4 + (2-4t/7)
2 = 2-4t/7
14 = 2-4t
4t = 2 - 14
4t = -12
t = -3 //

4 - (8-k/5) = (2k/5)
4 = (2k/5) + (8-k/5)
4 = (2k+8-k)/5
4 = (k+8)/5
20 = k + 8
k = 12 //

(9/2) + (8+k/6) = (10+3k/5)
(27/6) + (8+k/6) = (10+3k/5)
(27+8+k)/6 = (10+3k/5)
(35+k)/6 = (10+3k/5)
5(35+k) = 6(10+3k)
175+5k = 60+18k
13k = 115
k = 115/13
k = 8 又 11/13 //

1) 6-2+4t/7=4 2) 4-(8-k/5)=2k/5 3) 9/2+8+k/6=10+3k/5
4+4t/7=4 4-8+k/5=2k/5 9/2+16/2+k/6=20/2+3k/5
4t/7=4-4 -4+k/5=2k/5 25/2+k/6=20/2+3k/5
4t/7=0 -4=2k/5-k/5 5/2+k/6=3k/5
4t=0*7 -4=k/5 30*(5/2+k/6)=30*3k/5
4t=0 -4*5=k 75+5k=18k
t=0 k=-20 18k=5k+75
(18-5)k=75
13k=75
k=75/13

1) 6-(2-4t/7)=4
12-24t/7=4
12-24t=28
-24t=16
t=-16/24
t=-2/3

2) 4-(8-k/5)=2k/5
4=8-k+2k/5
20=8-k
-12=k

3) 9/2+8+k/6=10+3k/5
4.5=60+18k-40-5k/30
135=20+13k
k=115/13