請各位多多幫忙吧!!(中一Maths...)PLEASE QUICE!!!

1) 7[5(x-3)+12] = [7-4(x+5)]
35x - 105 + 84 = 7 - 4x - 20
35x - 21 = -4x -14
35x + 4x = 21 - 14
39x = 7
x = 7/39 //

2) a-1/4(分數)=2-a=2/3(分數) *** ?????(點解會有兩個=)

3) d/8(分數)-d/18(分數)=10
18d/144 - 8d/144 = 10 (通分母)
10d/144 = 10
10d = 1440
d = 144 //

4) x-x-1/2(分數) = 2-x+2/3(分數)
(2x/2) - [(x-1)/2] = (6/3) - [(x+2)/3] (通分母)
(2x-x+1)/2 = (6-x-2)/3
(x+1)/2 = (4-x)/3
3(x+1) = 2(4-x)
3x+3 = 8-2x
5x = 5
x = 1 //

5) k/3(分數)+3k+4/9(分數)=2-3k/12(分數)
(3k/9) + (27k/9) + (4/9) = 2 - (k/4) (通分母)
(3k+27k+4)/9 = (8/4) - (k/4)
(30k+4)/9 = (8-k)/4
4(30k+4) = 9 (8-k)
120k + 16 = 72 - 9k
129k = 56
k = 56/129 //

6) 3x-2/5(分數)-13/25(分數)=8(3-x)/3(分數)
[5(3x-2)]/25) - 13/25 = (24-8x)/3
(15x-10-13)/25 = (24-8x)/3 (通分母)
(15x-23)/25 = (24-8x)/3
3(15x-23) = 25(24-8x)
45x - 69 = 600 - 200x
245x = 669
x = 669/245
x = 2 又 179/245 //

7) y/4(分數)-5(3-y)/3(分數)=2y-17/6(分數)
(3y/12) - (60-20y)/12 = 12y/6 - 17/6 (通分母)
(3y-60+20y)/12 = (12y-17)/6
(23y-60)/12 = (12y-17)/6
(23y-60)/2 = (12y-17)
23y - 60 = 2 (12y-17)
23y - 60 = 24y - 34
y = -26 //

8) 2y-y=9
y = 9 //


9) 5y-r/3(分數)=d *** ????? (求y or r or d)

10) 3y+8=6k *** ????? (求y or k)

11) -8r+5qy=-7q *** ????? (求r or qy or q)

12) 7(a-by)=5(a+2b) *** ????? (求?)

13) a(3y-2b)=c(d+3e) *** ????? (求?)

問題9-13, 不明白做什麼? 不懂得答.

...
你的問題太多了吧-.-
雖然是簡淺問題...高lv的人很快做完- -
但希望你能嘗試吧

我幫你做幾題啦...其他自己試下-.-如果唔係你乜都學唔到

1) 7[5(x-3)+12]=[7-4(x+5)]
7[(5x-15)+12]=[7-(4x+20)]
7(5x-3)=(7-4x-20)
35x-21=(-4x)-13
35x+4x=21-13
39x=8
x=8/39

2) a-1/4=2-a=2/3
a=2/3+1/4
a=8/12+3/12
a=11/12
-.-條問題好似有問題/定係我計錯@@
3) d/8-d/18=10
9d/72-4d/72=10
5d/72=10
5d=720
d=144
4) x-x-1/2=2-x+2/3
-1/2=6/3+2/3-x
x=8/3+1/2
x=16/6+3/6
x=19/6

我唸分數點通分母你應該識啦

8) 2y-y=9
2y-1y=9
y(2-1)=9
y=9

9題之後佢想你做咩?簡化?

-,-其他未知想做乜幫唔到你
加油!!@@