一題多項式!!!
回答 (3)
2006-11-29 5:31 am
✔ 最佳答案
你想因式分解定展開呀... 等我俾曬兩個你:因式分解: 4t[(4t + 3) - 3(4t + 3)]
= 4t[-2(4t + 3)]
= 4t (-8t - 6)
= -32t^2 -24t
= -8t(4t + 3)
展開: 4t[(4t + 3) - 3(4t + 3)]
= 4t(-8t -6)
= -32t^2 - 24t
參考: me ar ... trust me! I do it be myself~~
2006-11-29 5:40 am
4t[(4t + 3) - 3(4t + 3)]
= 4t[-2(4t + 3)]
= 4t (-8t - 6)
= -32t^2 -24t
~^^~ = -8t(4t + 3) ~^^~
= 4t[-2(4t + 3)]
= 4t (-8t - 6)
= -32t^2 -24t
~^^~ = -8t(4t + 3) ~^^~
參考: ~^^~me
2006-11-29 5:31 am
4t[(4t+3)-3(4t+3)]
=4t(4t+3)[1-3]
=4t(4t+3)[(-2)
設y=4t(4t+3)[(-2)
代y=0
4t(4t+3)[(-2)=0
-32t^2-24t=0
t=-0.75或t=0
=4t(4t+3)[1-3]
=4t(4t+3)[(-2)
設y=4t(4t+3)[(-2)
代y=0
4t(4t+3)[(-2)=0
-32t^2-24t=0
t=-0.75或t=0
收錄日期: 2021-04-23 23:28:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061128000051KK04303