Prove the following expressions.
n．n-1Ck = (n-k) nCk
Binomial Theorem(A.Maths)
2006-11-28 2:46 am
回答 (1)
2006-11-28 2:53 am
✔ 最佳答案
n．n-1Ck =n[(n-1)!/k!(n-1-k)!]
=n!/k!(n-1-k)!
=(n-k)n!/k!(n-1-k)!(n-k)
=(n-k)n!/k!(n-k)!
=(n-k) nCk
收錄日期: 2021-04-25 16:49:54
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https://hk.answers.yahoo.com/question/index?qid=20061127000051KK03171