一條數學題.....................thx!!!

7[2(y-3)+y] = 4[1-3(y+2)]
7(2y - 6 + y) = 4(1 - 3y - 6)
14y - 42 + 7y = 4 - 12y - 24
21y - 42 = -20 - 12y
21y + 12y = -20 + 42
33y = 22
y = 22/33
y = 2/3

希望幫到你

2006-11-26 22:49:34 補充：
上面那位朋友7[2y-6 y] = 4[1-3y 6]

2006-11-26 22:51:44 補充：
又食字...........知唔知點解成日食左 d 字.........上面那位朋友7[2y - 6y] = 4[1-3y-6]才是正確是 -6 不是 6

7[2(y-3)+y] = 4[1-3(y+2)]
7[2y-6+y]=4[1-3y-6]
14y-42+7y=4-12y-24
14y+7y+12y=4-24+42
33y=46-24
33y=22
2
y=---
3

Take the y=??.
7[2(y-3)+y]=4[1-3(y+2)]
7(2y-6+y)=4(1-3y-6)
14y-42+7y=4-12y-24
14y+7y+12y=4-24+42
33y=22
y=22/33

The highest one have some misakes...

2006-11-27 07:44:56 補充：
Add some morey=22/33Need to make it smallery=2/3

7[2(y-3)+y] = 4[1-3(y+2)]

7(2y-6+y) = 4(1-3y-6)

7(3y-6) = 4(-5-3y)

21y-42 = -20-12y

21y+12y = -20+42

33y = 22

y = 22/33

y = 2/3