Given that the angles of a triangle are(6x度+40度),(x度+30度) and (3x度-10度) and (3x度-10度),find
(a) the value of x.
(b) the obtuse angle of this triangle.
MATHS QUESTIONs??
2006-11-27 1:27 am
回答 (2)
2006-11-27 1:50 am
✔ 最佳答案
Given that the angles of a triangle are(6x度+40度),(x度+30度) and (3x度-10度) find (a) the value of x.
三角形的內角和為180o
則
(6x + 40) + (x + 30) + (3x – 10) = 180
10x + 60 = 180
10x = 120
x = 12o
(b) the obtuse angle of this triangle.
這三角形的純角為
6x + 40
= 6*12 + 40
= 112o
2006-11-27 2:28 am
(6x + 40) + (x + 30) + (3x – 10) = 180
10x + 60 = 180
10x = 120
x = 12o
這三角形的純角
6x + 40
= 6*12 + 40
= 112o
10x + 60 = 180
10x = 120
x = 12o
這三角形的純角
6x + 40
= 6*12 + 40
= 112o
參考: 自己
收錄日期: 2021-04-11 16:26:37
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