紅十字會將6x袋米分派給四個災區的人士。首三個分別得到(2x+30)袋、(x+90)袋及(300-x)袋米。
(a)問第四個災區會得到米多少袋?
(b)若第四個災區得到180袋米,求x的值。
數學方程式 ....超急 ....
2006-11-26 11:59 pm
回答 (5)
2006-11-27 12:07 am
(a) Let a be the number of bags for the 4th Region
(2x+30) + (x+90) + (300-x) + a = 6x
(2x+x-x) + (30+90+300) + a = 6x
a = 6x - 2x - 420
a = 4x - 420
(b) If a = 180, find x
180 = 4x - 420
4x = 600
x = 150
(2x+30) + (x+90) + (300-x) + a = 6x
(2x+x-x) + (30+90+300) + a = 6x
a = 6x - 2x - 420
a = 4x - 420
(b) If a = 180, find x
180 = 4x - 420
4x = 600
x = 150
參考: myself
2006-11-27 12:06 am
(b)6x-(2x+30)-(x+90)-(300-x)=180
吾知岩吾岩喎...睇下啦...a就吾識啦...
吾知岩吾岩喎...睇下啦...a就吾識啦...
2006-11-27 12:05 am
(a)
6x - [(2x+30)+(x+90)+(300-x)]
= 6x - (2x+30+x+90+300-x)
= 6x - (2x + 420)
= 6x - 2x - 420
= 4x - 420
(b)
4x -420 = 180
4x = 600
x = 125
2006-11-26 16:06:02 補充：
sorry, x should be 150
6x - [(2x+30)+(x+90)+(300-x)]
= 6x - (2x+30+x+90+300-x)
= 6x - (2x + 420)
= 6x - 2x - 420
= 4x - 420
(b)
4x -420 = 180
4x = 600
x = 125
2006-11-26 16:06:02 補充：
sorry, x should be 150
2006-11-27 12:04 am
(a)問第四個災區會得到米y袋
6x = (2x + 30) + (x + 90) + (300 - x) + y
y = 6x - 2x - x + x - 30 - 90 -300
y = 4x - 420
(b)若第四個災區得到180袋米
180 = 4x - 420
x = 600 / 4
x = 150
6x = (2x + 30) + (x + 90) + (300 - x) + y
y = 6x - 2x - x + x - 30 - 90 -300
y = 4x - 420
(b)若第四個災區得到180袋米
180 = 4x - 420
x = 600 / 4
x = 150
2006-11-27 12:03 am
a) 第四袋︰ 6x-(2x+30)-(x+90)-(300-x)
=4x-420
b) 如果4x-420=180 4x=600 x=150
=4x-420
b) 如果4x-420=180 4x=600 x=150
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