Q.1
4x^4 - 17x^2+4=0
Q.2
9^[x(x+1)] = 27^(x+1)
f.4 math呀
2006-11-26 9:33 pm
回答 (1)
2006-11-26 9:46 pm
✔ 最佳答案
4x^4 - 17x^2+4=0(4x^2-1)(x^2-4)=0
x^2=1/4 or x^2=4
x=1/2 or -1/2 or 2 or -2 (有答案要reject(剔除),請自己試)
9^[x(x+1)] = 27^(x+1)
3^2[x(x+1)] = 3^3(x+1)
2[x(x+1)] = 3(x+1)
2x^2+2x-3x-3=0
2x^2-x-3=0
(x+1)(2x-3)=0
x= -1 or x=3/2
收錄日期: 2021-04-23 16:17:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061126000051KK02237