問數學題!!~10~

(1).

6t / 4tu

1st step: Divide by “t”
= (6t / t) / (4tu / t)
= 6t / 4u

2nd step: Divide by “2”
= (6 / 2) / (4u / 2)
= 3 / 2u (Answer)

(2).

15a²b/9b

1st step: Divide by “b”
= (15a²b / b) / (9 / b)
= 15a² / 9

2nd step: Divide by “3”
= (15a² / 3) / (9 / 3)
= 5a² / 3 (Answer)

(3).

ab-ac/ab+ac
= ab - ac/ab + ac
= ab - (c/b) + ac

Therefore,
ab-ac/ab+ac = ab - (c/b) + ac BUT NOT a+c/3

(4).

5ab+10a/3a

1st step: Divide by “a”
= (5ab + 10a) / (3a)
= a (5b + 10) / 3a
= [a (5b + 10) / a] / [3a / a]
= (5b + 10) / 3

2nd step: Change “(5b + 10)” to “[5 (b + 2)]”
= (5b + 10) / 3
= [5 (b + 2)] / 3 (Answer)

1.3/u

2.5a二次方/3

3.-1

4.5(b+2)/3