數學-因式分解
回答 (3)
2006-11-24 3:31 pm
✔ 最佳答案
You must know these formula:(x+y)²
=x²+2xy+y²
And
a²+2ab+b²
=(a+b)²
In this question:
(x²)(y²)+(z²)+2xyz
=x²y²+z²+2xyz
=x²y²+2xyz+z²
Get back in place
=(xy+z)²
2006-11-24 3:19 pm
x^2y^2= (xy)^2 (a^2)
2xyz (2ab)
z^2 (b^2)
因為 a^2+2ab+b^2=(a+b)^2
所以
(x^2)(y^2)+(z^2)+2xyz
= (xy)^2+2xyz+z^2
=(xy+z)^2
2xyz (2ab)
z^2 (b^2)
因為 a^2+2ab+b^2=(a+b)^2
所以
(x^2)(y^2)+(z^2)+2xyz
= (xy)^2+2xyz+z^2
=(xy+z)^2
參考: 我自己
2006-11-24 11:41 am
x²y² + z² + 2xyz
= (xy)² + 2(xy)(z) + z²
= (xy+z)² 【因為 (a+b)² = a² + 2ab + b²】
希望幫倒你！^^
= (xy)² + 2(xy)(z) + z²
= (xy+z)² 【因為 (a+b)² = a² + 2ab + b²】
希望幫倒你！^^
參考: 我自己
收錄日期: 2021-04-23 18:53:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061124000051KK00430