F.1 Maths

(2a+3)/4 -(a+4)/3 = a+1
12 x [(2a+3)/4 -(a+4)/3] = 12 x (a+1)
3 x (2a + 3) - 4 x (a + 4) = 12a + 12
6a + 9 - 4a - 16 = 12a + 12
2a -7 = 12a + 12
2a - 12a = 12 + 7
-10a = 19
a = -19/10

(2a+3)/4-(a+4)/3=a+1
3(2a+3)-4(a+4)=12(a+1)
Both sides X12
6a+9-4a-16=12a+12
2a-12a=12-9+16
-10a=19
a=-19/10

Call me if there is misake

(2a+3)/4 -(a+4)/3 = a+1
12[(2a+3)/4 -(a+4)/3)] = 12(a+1)
(6a+9)-(4a+16) = 12a+1
6a+9 - 4a -16 =12a+1
2a+7 =12a+1
2a-12a =1-7
-10a = -6
a = -10/ -6
a = 5/3

(2a+3)/4 -(a+4)/3 = a+1
3(2a+3)/12 - 4(a+4)/12 = a+1
[3(2a+3) - 4(a+4)] /12 = a+1
[6a+9 - 4a+16] /12 = a+1
[2a+25] /12 = a+1
24a+300 = a+1
24a-a = 1-300
23a = -299
a = -13

3(2a+3)-4(a+4)=12(a+1)
6a+9-4a-16=12a+12
6a-4a-12a=12+16-9
-10a=19
a=-1.9

(2a+3)/4 -(a+4)/3 = a+1
(2a+3)/4-(a+4)=3a+3
(2a+3)-(a+4)=12a+12
2a+3-a-4=12a+12
a-12a=12+1
-11a=13
a=13/-11

(2a+3)/4-(a+4)/3=a+1
3(2a+3)-4(a+4)=12(a+1)
6a+9-4a-16=12a+12
-10a=19
a=-19/10

(2a+3)/4 -(a+4)/3 = a+1
3(2a+3)-4(a+4)=12(a+1)
6a+9-4a-16=12a+12
2a-7=12a+12
-19=10a
a=-1.9

(2a+3)/4 x 12 - (a+4)/3 X 12 = ( a+1)x 12

3(2a+3) - 4(a+4) = 12a+12

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