Maths question

4^(x+1) - 2^x = 3
2^(2x+2) - 2^x = 3
4*2^(2x) - 2^x = 3
4*(2^x)² - 2^x - 3 = 0

Let y = 2^x. Then,
4y² - y - 3 = 0
(4y+3)(y-1)=0
y = -3/4 or 1

So 2^x = -3/4 (Rejected since 2^x＞0) or 2^x = 1
2^x = 1
x = 0

Hope it helps! ^^

4^(x+1)-2^x = 3

4^x+4-2^x=3

2^x+4=3

2^x=-1

x=-1/2

4^(x+1) - 2^x = 3

4x+4-2x=3

2x=-1

x=-1/2