k(3x+5y)的2次方=?

2006-11-23 5:55 am

k(3x+5y)的2次方
=?
答案=9kx^2+30kxy+5yk^2
求條式

回答 (3)

2006-11-23 6:04 am

✔ 最佳答案

k(3x+5y)^2
=k(3x+5y)(3x+5y)
=k(3x(3x+5y)+5y(3x+5y))
=k(9x^2+15xy+15xy+25y^2)
=k(9x^2+30xy+25y^2)
=9kx^2+30kxy+25ky^2

參考: 我教數架

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2006-11-23 6:05 am

k(3x + 5y)²
= k[(3x + 5y)²]
= k[9x² + 30xy + 25y²]
= 9kx² + 30kxy + 25ky²

參考: me

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2006-11-23 6:01 am

是拆開佢就得!
k(3x+5y)^2
=k(3x+5y)(3x+5y)
=k(9x^2+30xy+5y^2)
=9kx^2+30kxy+5ky^2

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