The trace of a skew-Hermitian matrix is imaginary.
The eigenvalues of a skew-Hermitian matrix are imaginary.
Proof. Property (1) follows directly from property (2) since the trace is the sum of the eigenvalues. But one can also give a simple proof as follows. Let
圖片參考:http://images.planetmath.org:8080/cache/objects/4231/l2h/img19.png
, i.e.,
If x is an eigenvector of H with eigenvalue L, then
< Hx, x > = L< x,x >
< Hx, x > = < -H*x, x > = - < x, Hx > = - L*< x, x > where L* = conjugate
comparing, we have L = -L*. so L is pure imaginery.