4(a-b)^3-12(b-a)^2
要式
Factorize this expression...
2006-11-21 5:25 am
回答 (3)
2006-11-21 6:40 pm
✔ 最佳答案
4(a-b)^3-12(b-a)^2= 4(a-b)^3-12(a-b)^2
= 4 (a-b)^2 [(a-b) -3]
= 4(a - b - 3) (a - b)^2
2006-11-21 10:42:49 補充：
(a-b)^2 = (b-a)^2we can take out 4 (a-b)^2 at the same timeThe above solution can finish the question with the fewest steps
參考: I got grade A in both Maths and A Maths
2006-11-21 5:33 am
4(a-b)³-12(b-a)²
=4[(a-b)³-3(b-a)²]
=4[(a-b)³-3(b²-2ab+a²)]
=4[(a-b)³-3(a-b)²]
=4(a-b)²[(a-b)-3]
=4(a-b)²(a-b-3)
2006-11-20 21:34:51 補充：
2樓,(a b)² 不等於a² b²(a b)³ 不等於a³ b³
2006-11-20 21:36:23 補充：
1樓, (b-a)²=(b²-2ab＋a²)=(a-b)²
=4[(a-b)³-3(b-a)²]
=4[(a-b)³-3(b²-2ab+a²)]
=4[(a-b)³-3(a-b)²]
=4(a-b)²[(a-b)-3]
=4(a-b)²(a-b-3)
2006-11-20 21:34:51 補充：
2樓,(a b)² 不等於a² b²(a b)³ 不等於a³ b³
2006-11-20 21:36:23 補充：
1樓, (b-a)²=(b²-2ab＋a²)=(a-b)²
2006-11-21 5:31 am
4(a-b)^3-12(b-a)^2
=4(a^3-b^3)-12(b^2-a^2)
=4a^3-4b^3-12b^2+12a^2
=16a^3-16b^3
=4(a^3-b^3)-12(b^2-a^2)
=4a^3-4b^3-12b^2+12a^2
=16a^3-16b^3
收錄日期: 2021-04-12 22:51:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061120000051KK04490