Maths Patterns and Sequences

Give you some hints:

1) try to divide 4, 9, 16 by 2, 3, 4 respectively, you will get ......

2) try to divide the adjacent number :
108 / 72 = ???
162 / 108 = ???
243 / 162 = ???

1)1,4,9,16,25,36...
(1=4=9=16...)
1+3=4
4+5=9
9+7=16
16+9=25
25+11=36
....(+2)

2)m...........................................

Describe the pattern.
1) 1, 4, 9, 16, ...

The pattern is n^2.
The first term: n^2=1^2=1
The second term: n^2=2^2=4
The third term: n^2=3^2=9
The forth term: n^2=4^2=16
So, the pattern is n^2.

Write the sequence and write down its pattern and the next two terms.
2) 72, 108, 162, 243, ...

The pattern is: [3^(n+1)]*[2^(4-n)]
The first term: [3^(n+1)]*[2^(4-n)]=[3^(1+1)]*[2^(4-1)]=(3^2)(2^3)=72
The second term: [3^(n+1)]*[2^(4-n)]=[3^(2+1)]*[2^(4-2)]=(3^3)(2^2)=108
The third term: [3^(n+1)]*[2^(4-n)]=[3^(3+1)]*[2^(4-3)]=(3^4)(2^1)=162
The forth term: [3^(n+1)]*[2^(4-n)]=[3^(4+1)]*[2^(4-4)]=(3^5)(2^0)=243

The next terms:
[3^(n+1)]*[2^(4-n)]
=[3^(5+1)]*[2^(4-5)]
=(3^6)(2^-1)
=729*(1/2)
=364.5
The next second term:
[3^(n+1)]*[2^(4-n)]
=[3^(6+1)]*[2^(4-6)]
=2187*(1/4)
=546.75

1.
increase by 3 of the number befor

2.
唔識講=.=
sor~