Please make the letter in the square brackets the subject of the formula,thx.
1) 1/y = 1/x +C [x]
2) y=C + a-x/x [x]
F.2 Maths Changing subject(10分)
2006-11-21 1:30 am
回答 (5)
2006-11-21 1:36 am
✔ 最佳答案
1) 1/y = 1/x + C [x]1/x = 1/y - C
1/x = ( 1 - Cy ) / y
x = y / ( 1 - Cy )
2) y = C + a-x/x [x]
y = C + a/x - 1
a/x = y - C + 1
x = a / ( y - C + 1 )
2006-11-21 2:27 am
1.
1/Y=1/x+C
X=1/(1-YC)
2.
y=C+a-x/x
xy = C + a - x
xy - a - C = -x
x = - (xy - a - c)
x=-xy+a+c
1/Y=1/x+C
X=1/(1-YC)
2.
y=C+a-x/x
xy = C + a - x
xy - a - C = -x
x = - (xy - a - c)
x=-xy+a+c
2006-11-21 1:48 am
1)y = 1/x +C [x]
x=y+cxy
y=x-cxy
y=x(1-y)
x=y/(1-y)
2)y=C+a-x/x [x]
y=C+a/x-1
a/x =y-C+1
x =a/(y-C+1)
x=y+cxy
y=x-cxy
y=x(1-y)
x=y/(1-y)
2)y=C+a-x/x [x]
y=C+a/x-1
a/x =y-C+1
x =a/(y-C+1)
2006-11-21 1:43 am
1) 1/y= 1/x + C [x]
1/y-C=1/x
x= y-1/c
2) y= C+ a-x/x [x]
y-C= a-x/x
x(y-C)+x=a
x(y-c+1)=a
x=a/(y-c+1)
1/y-C=1/x
x= y-1/c
2) y= C+ a-x/x [x]
y-C= a-x/x
x(y-C)+x=a
x(y-c+1)=a
x=a/(y-c+1)
2006-11-21 1:33 am
1. x= (1-cy)/y
2. x= a/(y-c+1)
2006-11-20 17:35:03 補充：
Sorry, 第一題應是x= y/(1-cy)
2. x= a/(y-c+1)
2006-11-20 17:35:03 補充：
Sorry, 第一題應是x= y/(1-cy)
收錄日期: 2021-04-12 17:44:43
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