MATHS(代數)

1). Let the no of old monks is x and the no. of young monk is y

x + y = 100 (1)
3x + y/3 = 100 (2)

(2) ==== 9x + y = 300 (3)

(1) ==== y = 100 -x (4)

Put (4) into (3)

9x + (100 - x) =300
8x = 300 - 100
x = 25

y = 100 - x
= 100 - 25
= 27


(2) let the no. of organes be m and the no of box be n

m / 50 = n + 1 (1)

m / 55 = n - 1 (2)

(1) - (2)

m/50 - m/55 = (n+1) - (n-1)
m/50 - m/55 = 2
(55m - 50m) = 2 X 50 X 55
5m = 5500
m = 1100

Put m = 1100 into (1)
m / 50 = n + 1
1100/50 = n + 1
22 = n + 1
n = 21

1. Let a be the number og Elderly monks
Let b be the number og young monks

now we can write down the equation as follows:
a + b = 100 ..... (1)
3a + b/3 = 100 ..... (2)

from (1) we can get a = 100 - b... (3)
put (3) into (2), now we have
3(100- b) + b/3 = 100
b = 75
so, a = 100 -75 = 25

so there are 25 elderly monks and 75 young monks

2. Let a be the number of boxes
Let b be the number of orange

b/50 = a + 1
=> b = 50a+50 ..... (1)

b/55 = a- 1
=> b = 55a - 55 ..... (2)

put (1) into (2), we have

50a+50 = 55a -55
5a = 105
a = 21

and b = 50(21) + 50 = 1100

So we have 21 boxes and 1100 organges

2006-11-20 17:45:00 補充：
可能比較多字:答案(1)25 elderly Monks75 Young Monks答案(2)21 boxes1100 oranges