a) 2x - 1 - x^2
b) x^2 - 5x + 6
f.2因式分解
2006-11-20 3:13 am
回答 (4)
2006-11-22 3:42 pm
Q_a
2x-1-x²
=-x²-2x-1
=-(x²+2x+1)
=-(x+1)²
Q_b
x²-5x+6
=(x-2)(x-3)
2x-1-x²
=-x²-2x-1
=-(x²+2x+1)
=-(x+1)²
Q_b
x²-5x+6
=(x-2)(x-3)
2006-11-20 9:35 pm
a) 2x - 1 - x^2
=-x^2+2x-1
=-(x^2-x-x+1)
=-(x-1)^2
b) x^2 - 5x + 6
= x^2 - (2+3)x + 6
=x^2-2x-3x-6
=x(x-2)-3(x-2)
=(x-3)(x-2)
=-x^2+2x-1
=-(x^2-x-x+1)
=-(x-1)^2
b) x^2 - 5x + 6
= x^2 - (2+3)x + 6
=x^2-2x-3x-6
=x(x-2)-3(x-2)
=(x-3)(x-2)
2006-11-20 3:38 am
a) - ( X - 1 )^2
b) ( X - 2 ) ( X - 3 )
驗算
a) - (x - 1 )^2
= - ( x^2 -2x + 1 )
= 2x - 1 - x^2
b) ( x - 2 ) ( x - 3 )
= x^2 - 2x - 3x + 6
= x^2 - 5x + 6
b) ( X - 2 ) ( X - 3 )
驗算
a) - (x - 1 )^2
= - ( x^2 -2x + 1 )
= 2x - 1 - x^2
b) ( x - 2 ) ( x - 3 )
= x^2 - 2x - 3x + 6
= x^2 - 5x + 6
2006-11-20 3:22 am
ａ）
2x - 1 - x^2
＝（ｘ－１）＾２
ｂ）我唔知道．
（你有冇抄錯，好難喔～）
2x - 1 - x^2
＝（ｘ－１）＾２
ｂ）我唔知道．
（你有冇抄錯，好難喔～）
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