簡化...寫埋步驟
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更新1:
sorry...應該係.. (xy-2yz+4zx+1)-(yx+3yz+3)+(zx-7)+(yz+2zx-1)
F.1 數學問題...
回答 (6)
2006-11-19 10:35 pm
✔ 最佳答案
(xy-2yz+4zx+1)-(yx+3yz+3)+(zx-7)+(yz+zx-1)=p-j+u+o
=e
2006-11-19 14:39:58 補充：
(xy-2yz+4zx+1)-(yx+3yz+3)+(zx-7)+(yz+zx-1)=xy-2yz+4zx+1-yx-3yz-3+zx-7+yz+zx-1=xy-yx-2yz-2yz+4zx+zx+zx+1-3-7-1= -4yz+6zx-10
2006-11-19 10:23 pm
(xy-2yz+4zx+1)-(yx+3yz+3)+(zx-7)+(yz+zx-1)
=xy-2yz+4xz+1-xy-3yz-3+xz-7+yz+xz-1
=xy-xy+4xz+xz+xz-2yz-3yz+yz+1-3-7-1
=6xz-4yz-10
=2(3xz-2yz-5)
=xy-2yz+4xz+1-xy-3yz-3+xz-7+yz+xz-1
=xy-xy+4xz+xz+xz-2yz-3yz+yz+1-3-7-1
=6xz-4yz-10
=2(3xz-2yz-5)
參考: I am a maths teacher
2006-11-19 10:18 pm
(xy-2yz+4zx+1)-(yx+3yz+3)+(zx-7)+(yz+zx-1)
=xy-2yz+4zx+1-yx-3yz-3+zx-7+yz+zx-1
=xy-yx-2yz-3yz+yz+4zx+zx+zx+1-3-7-1
=-4yz+6zx-10
=2(3zx-2yz-5)
=xy-2yz+4zx+1-yx-3yz-3+zx-7+yz+zx-1
=xy-yx-2yz-3yz+yz+4zx+zx+zx+1-3-7-1
=-4yz+6zx-10
=2(3zx-2yz-5)
2006-11-19 10:15 pm
(xy-2yz+4zx+1)-(yx+3yz+3)+(zx-7)+(yz+zx-1)
=xy-2yz+4zx+1-yx-3yz-3+zx-7+yz+zx-1
=(xy-yx)+(-2yz-3yz+yz)+(4zx+zx+zx)+(1-1-3-7)
=-4yz+6zx-10
=6xz-4yz-10
=xy-2yz+4zx+1-yx-3yz-3+zx-7+yz+zx-1
=(xy-yx)+(-2yz-3yz+yz)+(4zx+zx+zx)+(1-1-3-7)
=-4yz+6zx-10
=6xz-4yz-10
2006-11-19 10:13 pm
(xy-2yz+4zx+1)-(yx+3yz+3)+(zx-7)+(yz+zx-1)
=xy-2yz+4zx+1-yx-3yz-3+zx-7+yz+zx-1
=xy-yx-2yz-3yz+yz+4zx+zx+zx+1-7-1
=-4yz+6zx-7
=xy-2yz+4zx+1-yx-3yz-3+zx-7+yz+zx-1
=xy-yx-2yz-3yz+yz+4zx+zx+zx+1-7-1
=-4yz+6zx-7
收錄日期: 2021-05-03 06:06:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061119000051KK02507