Thx for your question. This gives me a initiative to find the sol'n.
To construct a right angle triangle with adjasent sides of lenght 1 and 2, we will then obtain sqrt(5) and hence { sqrt(5) - 1 }.
Now, construct a right angle triangle with adjasent sides of lenght { sqrt(5) - 1 } and 2, we will then obtain sqrt{ 10 - 2 x sqrt(5) } . Let this number be 2L.
Finally, construt a circle with radius one and then use L to intersect the circumference of the circle, we will obtain the required pentagon!!
2006-12-02 17:05:49 補充:
Yes. Just use compass ( 圓規 ) can't do it. It could only be done by ruler and compass together.