解下列各方程 : (要有過程)
28y=2〔16ㄧ4(1ㄧy)〕
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very easy 的數學
2006-11-19 8:21 pm
回答 (6)
2006-11-19 8:26 pm
✔ 最佳答案
28y=2[16-4(1-y)]28y=2[16-4+4y]
28y=24+8y
20y=24
y=6/5 (or 1.2)
2006-11-19 9:32 pm
解下列各方程 : (要有過程)
28y=2〔16ㄧ4(1ㄧy)〕
28y=2(16-4+4y)
28y=2(12+4y)
28y=24+8y
28y - 8y=24
20y=24
y=24/20 = 6/5
28y=2〔16ㄧ4(1ㄧy)〕
28y=2(16-4+4y)
28y=2(12+4y)
28y=24+8y
28y - 8y=24
20y=24
y=24/20 = 6/5
參考: 自己
2006-11-19 9:09 pm
28y = 2(16 - 4(1 - y)〕
28y = 2(12 + 4y)
7y = 6 + 2y
y = 6/5
我諗唔會有錯掛 -.-
28y = 2(12 + 4y)
7y = 6 + 2y
y = 6/5
我諗唔會有錯掛 -.-
2006-11-19 8:43 pm
28y = 2〔16ㄧ4(1ㄧy)〕
28y = 2 (16 - 4 + 4y)
14y = 12 + 4y
10y = 12
y = 12/10
y = 6/5
一定是correct的!
28y = 2 (16 - 4 + 4y)
14y = 12 + 4y
10y = 12
y = 12/10
y = 6/5
一定是correct的!
2006-11-19 8:34 pm
28y = 2(16 - 4(1 - y)〕
28y = 2(12 + 4y)
7y = 2(3 + y)
7y = 6 + 2y
6 = 5y
y = 6/5
28y = 2(12 + 4y)
7y = 2(3 + y)
7y = 6 + 2y
6 = 5y
y = 6/5
2006-11-19 8:33 pm
28y=2〔16ㄧ4(1ㄧy)〕
28y= 2(16ㄧ4+4y)
28y=32-8+8y
20y=24
y=24/20= 6/5
28y= 2(16ㄧ4+4y)
28y=32-8+8y
20y=24
y=24/20= 6/5
收錄日期: 2021-04-12 23:08:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061119000051KK01807