ｃ／ｄ＋ｅ／４ｄ＝８ｃ
把公式主項變為ｄ
問數!!!!!（２０分＿）
2006-11-19 6:45 pm
回答 (9)
2006-11-19 6:51 pm
✔ 最佳答案
ｃ／ｄ＋ｅ／４ｄ＝８ｃ（４ｃ＋ｅ）／４ｄ＝８ｃ
（４ｃ＋ｅ）／８ｃ＝４ｄ
ｄ＝（４ｃ＋ｅ）／３２ｃ
2006-11-19 11:41:41 補充：
新增： １／ｘ－４ － ｘ／（４－ｘ）２次方 化簡．．． １／（ｘ－４）－ｘ／（４－ｘ）²＝－１／（４－ｘ）－ｘ／（４－ｘ）²＝［（－１）（４－ｘ）－ｘ］／（４－ｘ）²＝（－４＋ｘ－ｘ）／（４－ｘ）²＝－４／（４－ｘ）²
2006-11-19 11:48:49 補充：
T=6n 12(m-n) 公式主項變為n Ｔ＝６ｎ＋１２（ｍ－ｎ）Ｔ＝６ｎ＋１２ｍ－１２ｎＴ－１２ｍ＝－６ｎｎ＝（１２ｍ－Ｔ）／６
2006-11-19 12:00:18 補充：
Refer to " Mathematic - Love " Answer:The method he used is different from mine . However , the steps should be shown as follows:1/(x - 4) - x/(4 - x)²= 1/(x - 4) x/(x - 4)(4 - x) -------- Don ' t skip the " " mark...................................
2006-11-21 5:48 am
1.
c/d+e/4d=8c
4c/4d+e/4d=8c
(4c+e)/4d=8c
(4c+e)/8c=4d
1/2+e/8c=4d
1/8+e/32c=d
d=1/8+e/8c
OR
c/d+e/4d=8c
4c/4d+e/4d=8c
(4c+e)/4d=8c
4c+e=32cd
(4c+e)/32c=d
1/8+e/32c=d
d=1/8+32c
上面第一題全部答案都未約到最簡!(除了yemap01034)
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2.你條式寫得唔清楚,照常理就係(1/x)-4-x/(4-x)²(冇括號在x-4),但係上面D人都當係1/(x-4)-x/(4-x)²;仲有2次方係指全個x/(4-x)定係(4-x),所以E題答唔到你。
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3.
T=6n+12(m-n)
T=6n+12m-12n
T-12m=6n-12n
T-12m=-6n
(T-12m)/-6=n
-T/6+2m=n
上面答案未約到最簡!
c/d+e/4d=8c
4c/4d+e/4d=8c
(4c+e)/4d=8c
(4c+e)/8c=4d
1/2+e/8c=4d
1/8+e/32c=d
d=1/8+e/8c
OR
c/d+e/4d=8c
4c/4d+e/4d=8c
(4c+e)/4d=8c
4c+e=32cd
(4c+e)/32c=d
1/8+e/32c=d
d=1/8+32c
上面第一題全部答案都未約到最簡!(除了yemap01034)
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2.你條式寫得唔清楚,照常理就係(1/x)-4-x/(4-x)²(冇括號在x-4),但係上面D人都當係1/(x-4)-x/(4-x)²;仲有2次方係指全個x/(4-x)定係(4-x),所以E題答唔到你。
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3.
T=6n+12(m-n)
T=6n+12m-12n
T-12m=6n-12n
T-12m=-6n
(T-12m)/-6=n
-T/6+2m=n
上面答案未約到最簡!
參考: 數學能手Me
2006-11-20 1:37 am
Easy
1. (c/d) + (e/4d) = 8c
4c + e = 32cd (multiplying 4d on both sides)
d = (4c+e)/32c (dividing 32c on both sides)
2. you should know that (4-x)^2 = (x-4)^2
so [1/(x-4)] - [x/(4-x)^2]
= [1/(x-4)] - [x/(x-4)^2]
= (x-4-x)/(x-4)^2 (通分母)
= -4/[(x-4)^2]
3. T = 6n + 12(m-n)
T = 6n + 12m - 12n
T-12m = -6n
n = (12m-T)/6
1. (c/d) + (e/4d) = 8c
4c + e = 32cd (multiplying 4d on both sides)
d = (4c+e)/32c (dividing 32c on both sides)
2. you should know that (4-x)^2 = (x-4)^2
so [1/(x-4)] - [x/(4-x)^2]
= [1/(x-4)] - [x/(x-4)^2]
= (x-4-x)/(x-4)^2 (通分母)
= -4/[(x-4)^2]
3. T = 6n + 12(m-n)
T = 6n + 12m - 12n
T-12m = -6n
n = (12m-T)/6
參考: I am F.5 Maths Tutor
2006-11-19 7:23 pm
c/d+e/4d=8c
4c+e/4d=8c (通分母)
4c+e=(8c)(4d) (移項)
4d=4c+e/8c (移項)
d=4c+e/32c
4c+e/4d=8c (通分母)
4c+e=(8c)(4d) (移項)
4d=4c+e/8c (移項)
d=4c+e/32c
2006-11-19 7:07 pm
c/d+e/4d=8c
c/d+e=8c*4d
c=8c*4d*(d+e)
c=4(2c+d)(d+e)
c/4=2cd+d*d+2ce+de
c/4-2ce=2cd+d*d+de
c/4-2ce=d(2c+d+e)
(c/4-2ce)/(d)=(2c+d+e)
(c/4-2ce)/(d)-2c-e=d
(c/4-2ce)+(-2c-e)d=d*d
c/d+e=8c*4d
c=8c*4d*(d+e)
c=4(2c+d)(d+e)
c/4=2cd+d*d+2ce+de
c/4-2ce=2cd+d*d+de
c/4-2ce=d(2c+d+e)
(c/4-2ce)/(d)=(2c+d+e)
(c/4-2ce)/(d)-2c-e=d
(c/4-2ce)+(-2c-e)d=d*d
參考: me
2006-11-19 7:07 pm
c/d + e/4d = 8c
4c / 4d + e / 4d = 8c < 通分母
(4c + e)/4d = 8c < 把同類項合併
4c + e = 8c x 4d < 移項, 把4d移到另一方
4c + e = 32cd
(4c + e)/32c = d < 把32c移到另一方
d = (4c + e)/32c < 把公式主項的英文字母寫在左方
2006-11-19 11:12:35 補充：
化簡 1/(x - 4) - x/(4 - x)²1/(x - 4) - x/(4 - x)²= 1/(x - 4) x/(x - 4)(4 - x)= (4x - 4 x)/(x - 4)(4 -x)= (3x - 4)/(4x - x²)T = 6n 12(m - n)T = 6n 12m - 12nT = 12m - 6n6n = 12m - Tn = 2m - T/6
4c / 4d + e / 4d = 8c < 通分母
(4c + e)/4d = 8c < 把同類項合併
4c + e = 8c x 4d < 移項, 把4d移到另一方
4c + e = 32cd
(4c + e)/32c = d < 把32c移到另一方
d = (4c + e)/32c < 把公式主項的英文字母寫在左方
2006-11-19 11:12:35 補充：
化簡 1/(x - 4) - x/(4 - x)²1/(x - 4) - x/(4 - x)²= 1/(x - 4) x/(x - 4)(4 - x)= (4x - 4 x)/(x - 4)(4 -x)= (3x - 4)/(4x - x²)T = 6n 12(m - n)T = 6n 12m - 12nT = 12m - 6n6n = 12m - Tn = 2m - T/6
參考: me
2006-11-19 6:55 pm
c over d+e * 1 over 4d =8c
4cd over d+e = 8c
4cd =8c( d+e)
4cd =8cd + 8ce
4cd - 8cd = 8ce
全式除 4
cd - 2cd =2 ce
抽 factor
d(c-2c) = 2ce
d= 2ce over c-2c <----------------------------- ANSWER
4cd over d+e = 8c
4cd =8c( d+e)
4cd =8cd + 8ce
4cd - 8cd = 8ce
全式除 4
cd - 2cd =2 ce
抽 factor
d(c-2c) = 2ce
d= 2ce over c-2c <----------------------------- ANSWER
參考: 自己
2006-11-19 6:54 pm
/=?
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ｄ＋ｅ／４ｄ＝８ｃ＊ｃ
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ｃ／ｄ＋ｅ／４ｄ＝８ｃ
ｄ＋ｅ／４ｄ＝８ｃ＊ｃ
ｅ／３ｄ＝８ｃ２
ｄ＝８ｃ２ｅ／３
2006-11-19 6:53 pm
我想應該係咁
c/d+e/4d=8c
4c/4d+e/4d=8c
(4c+e)/4d=8c
4c+e=8c(4d)
4c+e=32cd
d=(4c+e)/32c
c/d+e/4d=8c
4c/4d+e/4d=8c
(4c+e)/4d=8c
4c+e=8c(4d)
4c+e=32cd
d=(4c+e)/32c
收錄日期: 2021-04-12 23:40:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061119000051KK01236