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2006-11-20 1:46 am
✔ 最佳答案
The above one missing the negative answers, so I give you the correct answer.t(1)= a=2
t(5)=ar^4=6*3^(1/3)
So, r^4 = 6*3^(1/3) / 2 = 3*3^(1/3) = 3^(4/3)
r = 3^(1/3) or r = -3^(1/3)
So, three geometric terms are:
ar, ar^2, ar^3
2*[3^(1/3)], 2*[3^(2/3)], 6 or -2*[3^(1/3)], 2*[3^(2/3)], -6
參考: myself, I am a F.5 Maths tutor
2006-11-19 9:04 am
t(1)= a=2
t(5)=ar^4=6*3^(1/3)
So, r^4 = 6*3^(1/3) / 2 = 3*3^(1/3) = 3^4/3
r = 3^1/3
So, three geometric terms are:
2* 3^1/3, 2* 3^2/3, 6 (equal to 2*3^3/3 )
t(5)=ar^4=6*3^(1/3)
So, r^4 = 6*3^(1/3) / 2 = 3*3^(1/3) = 3^4/3
r = 3^1/3
So, three geometric terms are:
2* 3^1/3, 2* 3^2/3, 6 (equal to 2*3^3/3 )
收錄日期: 2021-04-12 22:57:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061119000051KK00267