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👨🏻‍🏫 學術台數學

肥貓

2006-11-18 3:03 am

有無23既倍數係比118既倍數多1呀

回答 (7)

小李飛刀

2006-11-18 3:21 am

✔ 最佳答案

圖片參考：http://hk.yimg.com/i/icon/16/35.gif

23x-1=118y
x=2n-1
46n-23-1=118y
46n-24=118y
23n-12=59y
59y=(59,118,177,236,295,354,413,..............................)
(59,118,177,236,295,354,413,..............................)+12
=71,130,189,248,307,366,425.............
70/23...........2
129/23..........15
188/23...........5+23=28
2,15,5,18,8,21,11,1,14,4,17,7,20,10,23
59*15=885+12=897
23n-12=59y
23x-1=118y
n=39
y=15
x=2*39-1
x=77
23*77-1=1771-1
=1770

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Tom

2006-11-18 6:10 am

NO
118+1=119
119不能正整徐23
23*1=23
23*2=46
23*3=69
23*4=92
23*5=115
23*6=138
so 有眼看啦沒有

或者是:
119/23=5+4/23

請大家投我一票

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Hunter

2006-11-18 3:19 am

Since 8*118 - 23 * 41 = 1,
118 - 117 * (8*118 - 23 * 41 ) = 1
23 * (41 * 117) - (118 * 8) * 118 = 1

2006-11-17 23:37:15 補充：
to find: 8*118 - 23 * 41 = 1118 - 23*5 = 323 - 3*7 = 2So, 23 - (118 - 23*5) *7 = 2 3 - 2 = 1[118 - 23*5] - [23 - (118 - 23*5) *7]=1118*8 - 23*41 = 1

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Amby

2006-11-18 3:18 am

1771=23 x 77 = 15 x 118 +1

2006-11-17 19:20:55 補充：
the next one is 4485 = 23 x 195 = 118 x 38 1the next one is 7199 = 23 x 313 = 118 x 61 1the number are found by writing a very little program by myself

2006-11-17 19:22:25 補充：
The general term is 23 x (77 118n) = 118 x (15 23n) 1for n is any positive integer

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Man Wai

2006-11-18 3:12 am

無23既倍數係比118既倍數多1

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