The red cross distributed 6x packs of rice to four flooding areas.Three of the flooding areas got (2X+30)packs,(x+90)packs and (300-x)packs respectivelt.
A)how much packs of rice did the fourth flooding aera get?
B)If the fourth are got 180packs rice, find the value of x.
maths(代數)
2006-11-17 3:44 am
回答 (4)
2006-11-17 3:55 am
✔ 最佳答案
A)Let y be nos. of packs of rice for the fourth flooding area
6x = (2x+30) + (x+90) + (300-x) + y
6x = 2x + 420 + y
Hence,
y = 4x - 420
B)
If the fourth got 180 packs of rice, then
180 = 4x -420
Hence,
x = 150
2006-11-17 4:31 am
a) 6x-(2x+30)-(x+90)-(300-x)
=6x-2x-30-x-90-300+x
=4x-30-90-300
=4x-420
b) 4x-420=180
4x=180+420
4x=600
x=600/4
x=150
=6x-2x-30-x-90-300+x
=4x-30-90-300
=4x-420
b) 4x-420=180
4x=180+420
4x=600
x=600/4
x=150
參考: me
2006-11-17 3:51 am
A.)total no. of rice pack:
6x=2x+30+x+90+300-x+no. of pack 4th flooding area got
no. of pack 4th flooding area got=4x-420
B.)4x-420=180
4X=600
x=150
BTW, how many packs, NOT how much
forth, not fourth
6x=2x+30+x+90+300-x+no. of pack 4th flooding area got
no. of pack 4th flooding area got=4x-420
B.)4x-420=180
4X=600
x=150
BTW, how many packs, NOT how much
forth, not fourth
參考: myself
2006-11-17 3:47 am
a) 6x-(2x+30)-(x+90)-(300-x)
= 6x-2x-30-x-90-300+x
=4x-420
b) 4x-420=180
4x=600
x=150
= 6x-2x-30-x-90-300+x
=4x-420
b) 4x-420=180
4x=600
x=150
收錄日期: 2021-04-12 22:44:17
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