指數 f1架

2006-11-17 12:22 am
(-8)^4+7^2*(-2^6)
點計~要詳細解釋+步驟+快!
更新1:

hckckn已經錯了... 你要記住我既^6係系2既後面, 而非整個-2的後面喔..

回答 (5)

2006-11-17 12:28 am
✔ 最佳答案
(-8)^4+7^2*(-2^6)
= 8x8x8x8 + 7x7x(-2)x(-2)x(-2)x(-2)x(-2)x(-2)
= 64x64 +49x(64)
= 64x(64+49)
= 64x113)
=7232

2006-11-16 16:36:10 補充:
Corrections:(-8)^4+7^2*(-2^6)= 8x8x8x8 + 7x7x(-2x-2x-2x-2x-2x-2)= 64x64 - 49x(64)= 64x(64-49)= 64x15=960

2006-11-16 16:37:34 補充:
(-8)^4+7^2*(-2^6)= 8x8x8x8 + 7x7x(-2x2x2x2x2x2)= 64x64 - 49x(64)= 64x(64-49)= 64x15=960
2006-11-18 12:56 am
=(-8)*(-8)*(-8)*(-8)+7*7*-(2*2*2*2*2*2)
=4096+49*-(64)
=4096+49*-64
=4096+-3136
=4096-3136
=960
2006-11-17 6:32 am
(-8)^4+7^2x(-2^6)
=(-8x)(-8x)(-8x)(-8x)+[(7x7)(-2x-2x-2x-2x-2x-2)]
=4096+[49x64]
=4096+3136
=7232

**我都係中1架~~呢個式岩架喇...我做完好耐~

2006-11-16 22:46:10 補充:
唔該你寫個式寫好d喇...邊個出架!!!(-2^6)唔同-(2^6)架!!(-8)^4+7^2x-(2^6)=(-8x)(-8x)(-8x)(-8x)+(7^2x-(2x2x2x2x2x2)=4096+49x-64=4096-3136=960
參考: 自己計
2006-11-17 1:55 am
本來(-8)^4+7^2*(-2^6)
=(-8)*(-8)*(-8)*(-8)+7*7*(-2)*(-2)*(-2)*(-2)*(-2)*(-2)
=64*64+49*4*4*4
=64*64+49*64
=(64+49)64
=7232

但你講:
hckckn已經錯了...
你要記住我既^6係系2既後面, 而非整個-2的後面喔..
補充時間:2006-11-16 16:30:20



咁條式應該係:
(-8)^4+7^2*(-[2^6])
=(-8)*(-8)*(-8)*(-8)+7*7*-(2*2*2*2*2*2)
=4096+49*-(64)
=4096+(-3136)
=4096-3136
=960


條式係點嫁呢?比左兩個ANS你,你自己睇式然後簡啦!
參考: 1)My brain 2)Cauculator
2006-11-17 12:35 am
(-8)^4+7^2*(-2^6)

= -8x-8x-8x-8 + 7x7x-{(2)x(2)x(2)x(2)x(2)x(2)}

= 64x64 +49x(-64)

= 64x64-3136

=960

2006-11-19 14:19:50 補充:
kellylam824, 咁就奇la, hckckn係16:28:43做左個錯既答案, 但係於16:36就改番個正確答案, 佢個正確擺明係遲過我la, 我係16:35:01就已經俾左個正確既答案俾人la woo, 咁點解hckckn會係最佳答案ar????我(心如止水)起碼一早就計到360俾你la....其他人都計錯點解我唔係最佳答案ar???


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